y=1/8x^2+2

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Solution for y=1/8x^2+2 equation: 


x in (-oo:+oo)

y = (1/8)*x^2+2 // - (1/8)*x^2+2

y-((1/8)*x^2)-2 = 0

(-1/8)*x^2+y-2 = 0

-1/8*x^2 = -(y-2) // : -1/8

x^2 = -8*(2-y)

x^2 = -8*(2-y) // ^ 1/2

abs(x) = (-8)^(1/2)*(2-y)^(1/2)

x = (-8)^(1/2)*(2-y)^(1/2) or x = -((-8)^(1/2)*(2-y)^(1/2))

x in { (-8)^(1/2)*(2-y)^(1/2), -((-8)^(1/2)*(2-y)^(1/2)) }

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